3x^2=2704

Solution for 3x^2=2704 equation:

3x^2=2704

We move all terms to the left:

3x^2-(2704)=0

a = 3; b = 0; c = -2704;
Δ = b2-4ac
Δ = 02-4·3·(-2704)
Δ = 32448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{32448}=\sqrt{10816*3}=\sqrt{10816}*\sqrt{3}=104\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-104\sqrt{3}}{2*3}=\frac{0-104\sqrt{3}}{6}
=-\frac{104\sqrt{3}}{6}
=-\frac{52\sqrt{3}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+104\sqrt{3}}{2*3}=\frac{0+104\sqrt{3}}{6}
=\frac{104\sqrt{3}}{6}
=\frac{52\sqrt{3}}{3}
$